By what factor does the kinetic energy of a car change when its speed is doubled?|||From the formula, KE = (1/2)*m*v^2, where v is its speed.
Since v is doubled, then KE_NEW = (1/2)*m*(2v)^2 = 4*[(1/2)*m*v^2] = 4KE, so the kinetic energy is four times the original.|||let previous speed =y and new speed = x than it changes by the following equation (x-y)^2 *m/2|||by 2^2. from the fromula of kinetic energy = 1/2 m v^2
